[PDF]讲座A-B效应
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矢势和标势不为零,则运动着的两束相干的. 带电粒子,其波函数有可能会受矢势或标势. 的影响而出现不同的相位变化;. ▫ 提出了证实电A-B效应和磁A-B效应的可能 ...
Your assumption 1) is backwards. It is the charge that creates the electric field around it. Charge is an intrinsic property of matter, like mass it can be defined in certain units; correspondingly units are derived for the fields created around a charge which depend on the definition of charge units. – anna v Jul 7 '12 at 4:00
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No the photon doesn't carry charge. It doesn't emit an electromagnetic field. Why would you find this surprising? The qualitative statements you give do not imply the statement you say they imply. – Ron Maimon Jul 7 '12 at 6:03
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Remember, electromagnetic field is a distribution of electromagnetic force, not charge. Photon bosons are quantum of this field. So, they are force carriers.. not charge carriers. Only force is exchanged with these messenger particles. Based on this interaction, we determine charge of electrons etc involved. That's it!
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The following improvement of your statements eliminates the apparent contradiction:
The electromagentic field is the fundamental entity. Charges (electrons, positrons, nuclei) are accompanied by (''emit'') an electromagnetic field - a soft virtual photon cloud in terms of QED. Photons are elementary excitations of the quantum electromagnetic field. They do not carry charge. | |||
The previous answers are based on classical electromagnetism. If we consider this from a quantum-electrodynamic (QED) standpoint, it's not so simple. In QED, the force between charged fermions is exclusively conveyed by an uncharged boson quanta, photons. This changes the classical problem to "how do the charges know which electromagnetic force to generate, an attracting or repelling one?" I may be wrong about this, but the QED argument I believe is much more direct and leaves the original question open. In fact, I have contributed to this question, because for many years I have been unable to answer it.
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