Thursday, January 8, 2015

每隔二十年振荡一次的钟摆要多长? 平方根(钟摆长 / 9.8), 周期=2 x 3.14 x 平方根(钟摆长 / 9.8)

http://blog.sciencenet.cn/home.php?mod=space&uid=362400&do=blog&view=me&classid=123261&from=space&page=2

每隔二十年振荡一次的钟摆要多长?
已有 1382 次阅读 2013-12-5 08:38 |个人分类:立委科普|系统分类:科普集锦
How long does a pendulum need to be to swing once every 20 years?
The calculation points to 667,767 times the length between the Sun and the earth in a simplified model.


This question came out and got answered as I was proof-reading the final version of our translation on Prof. Church's article "A Pendulum Swung Too Far" which gives a historical account of the classical competition between rationalism and empiricism in science history and the implications on AI and NLP in the last 20 years and the coming generation.  Repeated patterns seem to reveal an arguable rule of each school taking the lead for about 20 years much like a pendulum although the last empiricist trend in NLP based on machine learning seems to run overtime and still shows no sign of swinging back.  A fascinating article we have had pleasure of reading and translating.


【立委按】这几天忙着最后校正翻译稿【Church:钟摆摆得太远】,其中揭示了科学历史上理性主义和经验主义像钟摆一样每20年各领风骚此消彼长的历史规律。于是有问:20年一次振荡的钟摆该 多长呢?这是一个科学问题,自然有科学的答案。因此促成此篇科普小品。


每隔二十多年振荡一次的钟摆要多长
日期: 12/04/2013 05:01:43


周期=2 x 3.14 x 平方根(钟摆长 / 9.8)

周期为20年,即3600x24x365x20秒 = 630720000秒。

平方根(钟摆长 / 9.8)= 630720000 / 6.28)= 100433121

钟摆长 / 9.8 = 100433121 x 100433121 = 10086800000000000

钟摆长 = 10086800000000000 x 9.8 = 98850800000000000米 = 98850800000000公里

地球到太阳的距离为149600000公里。这个钟摆的长度是地球到太阳距离的667,767倍,即约66万8千倍太阳到地球的距离。多少光年来着?

No comments:

Post a Comment